Two Binary Semaphores control one Task

gridsense wrote on Thursday, October 20, 2011:

I am thinking one vTask control by two binary semaphores, I am not sure how to do it properly. Say one is RTCSemaphore, another is UartSemaphore, both are given from ISR. Any ISR will trigger vTask from block state to running state. Here is my idea, is there some better way to do it?

vTask(void *pVParameters)
{

for(;:wink:
{
   if(xSemaphoreTake( RTCSemaphore, portMAX_DELAY) == pdTRUE)
    {
         DoRTCProcess(…);
     }
     else if(xSemaphoreTake( UARTSemaphore, portMAX_DELAY) == pdTRUE)
    {
        ProcessUartData(…);
     }

}

}

davedoors wrote on Thursday, October 20, 2011:

Use a queue instead of a semaphore, and post a message to the queue that says where the message came from:

xQueueReceive( &xMessage, portMAX_DELAY )
switch( xMessage )
{
	case _RTC_ :  DoRTCProcess(..); break;
	case _UART_:  ProcessUartData(..); break;
}

Then in the interrupts use xQueueSendFromISR() instead of xSemaphoreGiveFromISR().

gridsense wrote on Friday, October 21, 2011:

Thanks. Your idea is better than mine.